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To determine the distance traveled by a train in the sixth second, we need to use the equations of motion. In this case, we have an object starting from rest (v0=0v_0 = 0) with a uniform acceleration (a=4.0 m/s2a = 4.0 , ext{m/s}^2).

The equation that relates distance (dd), initial velocity (v0v_0), acceleration (aa), and time (tt) is:

d=v0⋅t+12⋅a⋅t2d = v_0 cdot t + frac{1}{2} cdot a cdot t^2

Plugging in the values:

v0=0 m/sv_0 = 0 , ext{m/s} a=4.0 m/s2a = 4.0 , ext{m/s}^2 t<mo

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