+26 votes
in Classical Mechanics by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+13 votes
by

The coefficient of friction is a dimensionless quantity that represents the ratio of the frictional force between two surfaces to the normal force pressing them together. It is denoted by the symbol "μ" (mu).

If we change either the frictional force or the normal force, the coefficient of friction can be affected in the following ways:

  1. Changing the frictional force:

    • If the frictional force changes while the normal force remains constant, the coefficient of friction will also change.
    • The coefficient of friction is determined by the ratio of the frictional force to the normal force. Therefore, if the frictional force increases, the coefficient of friction will also increase, assuming the normal force remains constant.
    • Conversely, if the frictional force decreases, the coefficient of friction will decrease, assuming the normal force remains constant.
  2. Changing the normal force:

    • If the normal force changes while the frictional force remains constant, the coefficient of friction will also change.
    • The coefficient of friction is determined by the ratio of the frictional force to the normal force. Therefore, if the normal force increases, the coefficient of friction will decrease, assuming the frictional force remains constant.
    • Conversely, if the normal force decreases, the coefficient of friction will increase, assuming the frictional force remains constant.

It's important to note that the coefficient of friction is a property of the interface between two surfaces and remains constant for a given pair of materials under specific conditions (e.g., dry surfaces, no lubrication). However, changing the frictional force or the normal force can affect the effective coefficient of friction experienced in a particular situation.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...