To calculate the distance traveled by the car, we can use the equation:
s=ut+12at2s = ut + frac{1}{2}at^2s=ut+21at2
Where:
- sss is the distance traveled
- uuu is the initial velocity
- ttt is the time
- aaa is the acceleration
Given: u=8 m/su = 8 , ext{m/s}u=8m/s a=2 m/s2a = 2 , ext{m/s}^2a=2m/s2 t=10 st = 10 , ext{s}t=10s
Substituting these values into the equation, we get:
s=(8 m/s)(10 s)+12(2 m/s2)(10 s)2s = (8 , ext{m/s})(10 , ext{s}) + frac{1}{2}(2 , ext{m/s}^2)(10 , ext{s})^2s=(8m/s)(10s)+21(2m/s2)(10s)2
Calculating this equation gives us:
s=80 m+12(2 m/s2)(100 </mtext