To calculate the distance traveled by the car in 6 seconds, we can use the following equation of motion:
s = ut + (1/2)at^2
where: s = distance traveled u = initial velocity t = time a = acceleration
Given: u = 2 m/s (initial velocity) t = 6 s (time) a = 2 m/s² (acceleration)
Plugging in the values, we can calculate the distance traveled:
s = ut + (1/2)at^2 s = (2 m/s)(6 s) + (1/2)(2 m/s²)(6 s)^2 s = 12 m + (1/2)(2 m/s²)(36 s^2) s = 12 m + (1/2)(2 m/s²)(36 s^2) s = 12 m + (1/2)(2 m/s²)(1296 s^2) s = 12 m + 1296 m s = 1308 m
Therefore, the car travels a distance of 1308 meters in 6 seconds.