Question

A motorcycle is moving with a velocity of 40 m/s squared. It gets acceleration at a rate of 8 MS. How much distance will it cover in the next 10 seconds?

Answer 1

There seems to be a misunderstanding in the units you provided for velocity and acceleration. Velocity is typically measured in meters per second (m/s), while acceleration is measured in meters per second squared (m/s²). It appears that the units you provided for velocity and acceleration are incorrect.

Assuming the velocity of the motorcycle is 40 m/s and it accelerates at a rate of 8 m/s², we can calculate the distance it will cover in the next 10 seconds using the following kinematic equation:

$d=v_{0}t+\frac{1}{2}a{t}^2$

where: d = distance covered v₀ = initial velocity t = time a = acceleration

Plugging in the values: v₀ = 40 m/s a = 8 m/s² t = 10 s

$d=(40\times 10)+\frac{1}{2}(8\times 10^2)$

$d=400+\frac{1}{2}\times 800$

$d=400+400$

$d=800$

Therefore, the motorcycle will cover a distance of 800 meters in the next 10 seconds.