To determine the velocity of the ball after 2 seconds, we need to consider the effect of gravity on its motion.
When the ball is thrown upward, it moves against the force of gravity, causing its velocity to decrease. At the highest point of its trajectory, the ball momentarily stops moving upward and starts to fall downward due to gravity. Therefore, the velocity of the ball after 2 seconds will depend on the acceleration due to gravity and the initial velocity.
In the absence of any other forces like air resistance, we can assume the acceleration due to gravity to be approximately 9.8 m/s². Since the ball was thrown upward, its initial velocity is positive (+10 m/s). After 2 seconds, the ball will have been affected by gravity for a total of 2 seconds, both during the upward and downward phases.
To find the final velocity of the ball after 2 seconds, we can use the following formula:
v = u + at
where: v = final velocity u = initial velocity a = acceleration t = time
Substituting the values into the formula:
v = 10 m/s + (9.8 m/s²)(-2 s)
Note that we use a negative sign for the acceleration because it acts opposite to the initial velocity during the downward phase.
Calculating the expression:
v = 10 m/s - 19.6 m/s v = -9.6 m/s
Therefore, the velocity of the ball after 2 seconds is approximately -9.6 m/s, indicating that it is moving downward.