To solve this problem, we can use the equations of motion for uniformly accelerated motion. We have the initial velocity (u = 0 m/s), the final velocity (v = 20 m/s), and the mass of the tractor (m = 1500 kg).
- Acceleration (a): We can use the equation:
v = u + at
Rearranging the equation to solve for acceleration (a), we get:
a = (v - u) / t
Since the tractor starts from rest (u = 0), the equation simplifies to:
a = v / t
Plugging in the values, we have:
a = 20 m/s / t
- Time (t): We can calculate the time taken by the tractor using the equation:
v = u + at
20 m/s = 0 + a * t
Since the tractor starts from rest (u = 0), the equation simplifies to:
t = 20 m/s / a
- Distance covered (s): To find the distance covered by the tractor, we can use the equation:
s = ut + (1/2)at²
Since the tractor starts from rest (u = 0), the equation simplifies to:
s = (1/2)at²
Now, we substitute the value of t from the previous step into the equation to get:
s = (1/2)a * (20 m/s / a)²
Simplifying further, we have:
s = (1/2) * 20 m/s * 20 m/s / a
- Net force (F): The net force acting on an object can be calculated using Newton's second law:
F = m * a
Substituting the given mass of the tractor, we get:
F = 1500 kg * a
So, to summarize:
- Acceleration (a) = 20 m/s / t
- Time (t) = 20 m/s / a
- Distance covered (s) = (1/2) * 20 m/s * 20 m/s / a
- Net force (F) = 1500 kg * a
To find the values of acceleration, distance covered, and net force, we need to calculate the value of acceleration first.