Question

A car moves with an initial velocity of 15 m/s and accelerates with constant acceleration 4 m/s2 for 50 seconds. What is the total distance traveled?

Answer 1

To find the total distance traveled by the car, we can use the following kinematic equation:

s = ut + (1/2)at^2

Where: s = total distance traveled u = initial velocity t = time a = acceleration

Plugging in the given values: u = 15 m/s a = 4 m/s^2 t = 50 s

s = (15 * 50) + (1/2) * 4 * (50^2) s = 750 + 1/2 * 4 * 2500 s = 750 + 2 * 2500 s = 750 + 5000 s = 5750 m

Therefore, the total distance traveled by the car is 5750 meters.