When an object is dropped from a height with an initial velocity of zero and neglecting air drag, its speed can be determined using the equation for the final velocity of an object undergoing free fall:
v=2ghv = sqrt{2gh}v=2gh
where:
- vvv is the final velocity (speed) of the object
- ggg is the gravitational acceleration (approximately 9.8 m/s² on Earth)
- hhh is the height from which the object is dropped
Since the initial velocity is zero, the final velocity will be the speed at which the object hits the ground.
Let's assume the object is dropped from a height of hhh meters. Plugging in the values:
v=2⋅9.8⋅hv = sqrt{2 cdot 9.8 cdot h}v=2⋅9.8⋅h
Simplifying:
v=19.6hv = sqrt{19.6h}v=19.6h
Therefore, the speed of an object dropped from a height hhh with an initial velocity of zero and neglecting air drag is given by the square root of 19.619.619.6 times the height hhh.