An object at the end of a rope has a centripetal acceleration of 145 m/s2 , and the length of the rope is 0.34 m. What is the tangential velocity of the object?

Question

Your answer

Daniel1951 · Answer 1 · 2023-01-19T10:03:25+0000

To find the tangential velocity of the object, we can use the relationship between centripetal acceleration and tangential velocity.

The centripetal acceleration (ac) is related to the tangential velocity (v) and the radius (r) of the circular path by the equation:

ac = (v^2) / r

In this case, the centripetal acceleration is given as 145 m/s^2, and the radius of the circular path is the length of the rope, 0.34 m.

Rearranging the equation, we can solve for the tangential velocity:

v = sqrt(ac * r)

Substituting the given values:

v = sqrt(145 m/s^2 * 0.34 m)

Calculating this expression:

v = sqrt(49.3 m^2/s^2)

v ≈ 7.02 m/s

Therefore, the tangential velocity of the object is approximately 7.02 m/s.