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To determine the maximum height (h) and the corresponding angle at which the ball can strike the wall, we need to consider the projectile motion of the ball. Assuming there is no air resistance, we can use the equations of motion to solve this problem.

Let's assume that the initial velocity of 18 m/s is split into horizontal (Vx) and vertical (Vy) components. The vertical component determines the maximum height, while the horizontal component determines the time of flight.

  1. Horizontal Component: The horizontal velocity (Vx) remains constant throughout the motion, as there is no horizontal acceleration. Therefore, the horizontal distance traveled by the ball is determined by the time of flight (t) and the horizontal velocity.

Since the ball will eventually strike the wall, we need to find the time it takes to reach the wall. Let's assume the distance to the wall is represented by 'd'. Using the equation: distance = velocity × time, we have: d = Vx × t

  1. Vertical Component: The vertical motion of the ball can be analyzed using the equation of motion for vertical displacement. The ball will reach its maximum height when the vertical component of velocity becomes zero. At that point, the ball will start to descend towards the wall.

The equation for vertical displacement (h) at maximum height is given by: h = (Vy^2) / (2g)

Where:

  • h is the maximum height.
  • Vy is the vertical component of the initial velocity.
  • g is the acceleration due to gravity (approximately 9.8 m/s²).
  1. Finding the Angle: The angle (θ) made by the ball with the horizontal can be determined using the tangent function: θ = arctan(Vy / Vx)

Let's plug in the given initial velocity (18 m/s) into these equations to find the maximum height (h) and the corresponding angle (θ):

Vx = 18 m/s (horizontal component) Vy = 0 m/s (at maximum height) g = 9.8 m/s² (acceleration due to gravity)

Using the equation for horizontal distance traveled: d = Vx × t

Since Vy = 0 at maximum height, we can use the equation for vertical displacement: h = (Vy^2) / (2g)

Finally, the angle can be determined using the tangent function: θ = arctan(Vy / Vx)

Unfortunately, we need additional information such as the distance to the wall or the time of flight to calculate the maximum height and the angle accurately. Could you please provide any additional details?

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