To determine the maximum height attained by an object thrown straight up with an initial velocity of 80 m/s, we need to consider the laws of motion and the effects of gravity.
When an object is thrown straight up, it moves against the force of gravity until it reaches its highest point, where its vertical velocity becomes zero. At this point, the object starts to fall back down.
To find the maximum height, we can use the equation for vertical displacement:
h = (v^2 - u^2) / (2g)
Where: h is the maximum height attained v is the final velocity (which is 0 m/s at the highest point) u is the initial velocity (80 m/s in this case) g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
Substituting the values into the equation:
h = (0^2 - 80^2) / (2 * 9.8) h = (-6400) / 19.6 h ≈ -326.53 meters
The negative sign indicates that the height is below the initial position. In this case, it means that the object will reach a maximum height of approximately 326.53 meters below the starting point before falling back down.