+27 votes
in Amplitude by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+27 votes
by

The Poynting vector is a mathematical quantity that represents the flow of energy associated with an electromagnetic wave. It describes both the direction and magnitude of the energy flow.

When calculating the energy of two different waves with different frequencies but the same amplitude using the Poynting vector, you might obtain the same results regardless of frequency. This can be explained by the fact that the Poynting vector is proportional to the square of the electric field amplitude and the frequency of the wave.

The energy carried by an electromagnetic wave is proportional to the square of the electric field amplitude. When comparing two waves with the same amplitude, the ratio of their energies will be the same regardless of frequency. This is because the energy is determined by the square of the amplitude, which eliminates the frequency dependency when the amplitudes are equal.

Mathematically, the expression for the Poynting vector is given by:

S = 1/μ₀ * E × B

Where: S is the Poynting vector, E is the electric field vector, B is the magnetic field vector, μ₀ is the permeability of free space.

The magnitude of the Poynting vector (|S|) represents the power per unit area carried by the electromagnetic wave. Integrating the magnitude of the Poynting vector over an area yields the total power or energy carried by the wave.

When comparing two waves with the same amplitude but different frequencies, the energy obtained by integrating the Poynting vector will be the same because the amplitude term dominates and the frequency term cancels out when calculating the total energy.

It's important to note that this holds true for waves with the same amplitude and different frequencies. If the amplitudes of the waves are different, or if the waves have different amplitudes and frequencies, the energy calculated using the Poynting vector would not be the same and would depend on both the amplitude and frequency of the waves.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...