If you have multiple sinusoids that are equally shifted in phase by 1 degree and have the same amplitude, you can calculate their sum by adding the individual sinusoids together.
Let's assume you have N sinusoids, each with an amplitude of A and equally shifted by 1 degree. The general equation for each sinusoid would be:
y(n) = A * sin(θn)
where n represents the index of the sinusoid, ranging from 1 to N, and θn represents the phase angle of the nth sinusoid.
To find the sum of these sinusoids, you can add them together:
y_sum = y(1) + y(2) + ... + y(N)
Using the equation for each sinusoid, we can substitute the values:
y_sum = A * sin(θ1) + A * sin(θ2) + ... + A * sin(θN)
If the phase angles are equally shifted by 1 degree, we can express them as multiples of the phase shift:
θn = n * 1 degree
Substituting this into the equation:
y_sum = A * sin(1 degree) + A * sin(2 degrees) + ... + A * sin(N degrees)
To calculate the sum, you would need to evaluate each term and add them together. However, it's important to note that for large values of N, the sum may not have a simple closed-form expression and might require numerical methods for accurate calculation.