No, the equation E = hv, where E represents the energy of a photon, h is the Planck's constant, and v is the frequency of the electromagnetic wave, does not imply that the energy carried by an electromagnetic wave is independent of its amplitude.
The equation E = hv relates the energy of a single photon to its frequency. In the context of electromagnetic waves, the energy carried by the wave as a whole is proportional to the square of the amplitude of the wave. The energy density (energy per unit volume) of an electromagnetic wave is directly proportional to the square of the electric field amplitude. Thus, higher-amplitude waves carry more energy than lower-amplitude waves.
In classical electromagnetism, the energy carried by an electromagnetic wave is determined by the wave's intensity, which is related to the square of the amplitude. The intensity is the power per unit area carried by the wave.
So, while the equation E = hv provides a relationship between the energy of a single photon and its frequency, it does not imply that the energy carried by an electromagnetic wave is independent of its amplitude. The energy of the wave depends on both its frequency and its amplitude.