To find the distance traveled by the particle in the fifth second, we can use the equations of motion. The relevant equation for this scenario is:
s = ut + (1/2)at^2
Where: s is the distance traveled u is the initial velocity a is the acceleration t is the time
Given: u = 48 m/s (initial velocity) a = -10 m/s^2 (acceleration due to gravity, negative because it acts in the opposite direction of the initial velocity) t = 5 s (time)
Plugging these values into the equation, we can calculate the distance traveled in the fifth second:
s = (48 m/s) * (5 s) + (1/2) * (-10 m/s^2) * (5 s)^2 s = 240 m - 125 m s = 115 m
Therefore, the distance traveled by the particle in the fifth second is 115 meters.