The rate of decomposition of O3 can be determined using the stoichiometry of the reaction and the given rate of formation of O2. According to the balanced equation:
2O3(g) -> 3O2(g)
The stoichiometric ratio between O3 and O2 is 2:3. This means that for every 2 moles of O3 that decompose, 3 moles of O2 are formed.
Given that the rate of formation of O2 is 1.5 x 10 mol/L, we can use this information to calculate the rate of decomposition of O3.
Using the stoichiometric ratio, we can set up the following relationship:
Rate of decomposition of O3 / 2 = Rate of formation of O2 / 3
Let's represent the rate of decomposition of O3 as "x." Plugging in the known values:
x / 2 = 1.5 x 10 mol/L / 3
Simplifying the equation:
x / 2 = 0.5 x 10 mol/L
Multiplying both sides by 2:
x = 1 x 10 mol/L
Therefore, the rate of decomposition of O3 is 1 x 10 mol/L.