To calculate the time it takes for the ball to fall to the surface of the Moon, we can use the equation of motion:
d = (1/2) * g * t^2
where: d = distance (1.50 m) g = acceleration due to gravity on the Moon (1.62 m/s^2) t = time
Rearranging the equation to solve for time (t):
t^2 = (2 * d) / g
t = sqrt((2 * d) / g)
Let's plug in the values:
t = sqrt((2 * 1.50) / 1.62)
Calculating this, we get:
t ≈ sqrt(2.94 / 1.62) t ≈ sqrt(1.81) t ≈ 1.34 seconds (rounded to two decimal places)
Therefore, the time it takes for the ball to fall to the surface of the Moon is approximately 1.34 seconds.