Question

A stone falls from a cliff and hits the ground below with a velocity of 60m/s. How long does the stone take to hit the ground above?

Answer 1

In order to determine the time it takes for the stone to hit the ground above, we need to consider the stone's initial velocity, its acceleration due to gravity, and the distance it needs to travel.

Assuming no air resistance, we can use the kinematic equation to calculate the time it takes for the stone to hit the ground above:

$v_f=v_i+at$

Where:

• $v_f$ is the final velocity (which is 0, as the stone comes to a stop when it hits the ground above).
• $v_i$ is the initial velocity of the stone, which is 60 m/s (given).
• $a$ is the acceleration due to gravity, which is approximately 9.8 m/s² (assuming no significant changes in elevation).
• $t$ is the time it takes for the stone to hit the ground above (what we're trying to find).

Rearranging the equation, we have:

$t=\frac{v_f-v_i}{a}$

Plugging in the values, we get:

$t=\frac{0-60}{-9.8}$

Simplifying the equation:

$t=<span\; class="mope$