To determine the height above the ground when the speed of the coin is 60.0 m/s, we can use the principles of free fall motion.
The initial height (h) of the coin is 3150 m, and we want to find the height when the speed (v) is 60.0 m/s.
We can use the equation for free fall motion:
v^2 = u^2 + 2as
Where: v = final velocity (60.0 m/s) u = initial velocity (0 m/s, as the coin is dropped from rest) a = acceleration due to gravity (-9.8 m/s^2, assuming downward as positive) s = displacement (change in height)
Rearranging the equation, we have:
s = (v^2 - u^2) / (2a)
Substituting the given values:
s = (60.0^2 - 0^2) / (2 * (-9.8)) s = (3600 - 0) / (-19.6) s = -183.673 m
The negative sign indicates that the displacement is in the opposite direction to the chosen positive direction (downward in this case).
To find the height above the ground, we subtract the displacement from the initial height:
Height above ground = Initial height - Displacement Height above ground = 3150 m - (-183.673 m) Height above ground = 3333.673 m
Therefore, when the speed of the coin is 60.0 m/s, it is approximately 3333.673 meters above the ground.