To determine the height of the tower and the velocity with which the ball hits the ground, we can use the equations of motion under constant acceleration.
Let's assume that the ball is dropped from rest, and we'll take the acceleration due to gravity as approximately 9.8 meters per second squared (9.8 m/s²) downward.
The equation to calculate the height (h) of the tower is given by:
h = (1/2) * g * t²
where g is the acceleration due to gravity and t is the time taken to reach the ground.
Substituting the given values: h = (1/2) * 9.8 m/s² * (5 s)² h = 122.5 meters
Therefore, the height of the tower is approximately 122.5 meters.
The velocity (v) with which the ball hits the ground can be calculated using the equation:
v = g * t
Substituting the given values: v = 9.8 m/s² * 5 s v = 49 m/s
Therefore, the velocity of the ball when it hits the ground is approximately 49 meters per second.