The distance covered by a freely falling body in two seconds can be calculated using the equations of motion. Assuming the body is falling vertically under the influence of gravity and neglecting air resistance, we can use the following equation:
distance = (1/2) * acceleration * time^2
In this case, the acceleration is equal to the acceleration due to gravity, which is approximately 9.8 meters per second squared (m/s^2). Plugging in the values:
distance = (1/2) * 9.8 * (2^2) = (1/2) * 9.8 * 4 = 19.6 meters
Therefore, a freely falling body would cover a distance of 19.6 meters in two seconds.