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To determine the initial horizontal velocity of the soccer ball, we can use the formula for horizontal distance traveled:

d=v0⋅td = v_0 cdot t,

where:

  • dd is the horizontal distance traveled (40.0 meters in this case),
  • v0v_0 is the initial horizontal velocity of the ball (the value we want to find), and
  • tt is the time of flight.

The time of flight can be determined using the formula for vertical displacement:

h=12gt2h = frac{1}{2} g t^2,

where:

  • hh is the vertical displacement (32.0 meters in this case),
  • gg is the acceleration due to gravity (approximately 9.8 m/s²), and
  • tt is the time of flight.

Rearranging the formula for vertical displacement, we have:

t=2hgt = sqrt{frac{2h}{g}}.

Substituting the given values into this equation, we find:

t=2⋅32.09.8≈2.04t = sqrt{frac{2 cdot 32.0}{9.8}} approx 2.04

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