To determine the final velocity of the ball just before it hits the ground and the height of the building, we need to make some assumptions and use the laws of motion. Let's assume the ball was dropped from rest (initial velocity = 0) and neglect air resistance.
First, we can use the equation of motion for free fall:
h = (1/2) * g * t^2
where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time of flight.
Rearranging the equation, we have:
h = (1/2) * g * t^2 2h = g * t^2 2h = 9.8 * (8.2)^2 2h = 673.56 h ≈ 336.78 meters
The height of the building is approximately 336.78 meters.
To find the final velocity of the ball just before it hits the ground, we can use another equation of motion:
v = u + g * t
where v is the final velocity, u is the initial velocity (0 in this case), g is the acceleration due to gravity, and t is the time of flight.
v = 0 + 9.8 * 8.2 v ≈ 80.36 m/s
The final velocity of the ball just before it hits the ground is approximately 80.36 m/s.