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To find the time required for the vehicle to attain a speed of 90 km/h, we can use the equation of motion for uniformly accelerated motion:

v=u+atv = u + at

Where:

  • vv is the final velocity (90 km/h)
  • uu is the initial velocity (30 km/h)
  • aa is the acceleration (1.8 m/s2^2)
  • tt is the time taken

First, let's convert the velocities from km/h to m/s:

Initial velocity, u=30 km/h×(1000 m1 km)×(1 h3600 s)=8.33 m/su = 30 , ext{km/h} imes left(frac{1000 , ext{m}}{1 , ext{km}} ight) imes left(frac{1 , ext{h}}{3600 , ext{s}} ight) = 8.33 , ext{m/s}

Final velocity, v=90 km/h×(1000 m1 km)×(1 h3600 s)=25 m/sv = 90 , ext{km/h} imes left(frac{1000 , ext{m}}{1 , ext{km}} ight) imes left(frac{1 , ext{h}}{3600 , ext{s}} ight) = 25 , ext{m/s}

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