To find the time required for the vehicle to attain a speed of 90 km/h, we can use the equation of motion for uniformly accelerated motion:
v=u+atv = u + atv=u+at
Where:
- vvv is the final velocity (90 km/h)
- uuu is the initial velocity (30 km/h)
- aaa is the acceleration (1.8 m/s2^22)
- ttt is the time taken
First, let's convert the velocities from km/h to m/s:
Initial velocity, u=30 km/h×(1000 m1 km)×(1 h3600 s)=8.33 m/su = 30 , ext{km/h} imes left(frac{1000 , ext{m}}{1 , ext{km}}
ight) imes left(frac{1 , ext{h}}{3600 , ext{s}}
ight) = 8.33 , ext{m/s}u=30km/h×(1km1000m)×(3600s1h)=8.33m/s
Final velocity, v=90 km/h×(1000 m1 km)×(1 h3600 s)=25 m/sv = 90 , ext{km/h} imes left(frac{1000 , ext{m}}{1 , ext{km}}
ight) imes left(frac{1 , ext{h}}{3600 , ext{s}}
ight) = 25 , ext{m/s}v=90km/h×(1km1000