The distance a ball falls in one second when dropped from a height of ten meters can be calculated using the equations of motion under constant acceleration due to gravity.
The equation for the distance fallen (d) in terms of time (t) when an object is dropped from rest is given by:
d = (1/2) * g * t^2
Where: d = distance fallen g = acceleration due to gravity (approximately 9.8 m/s^2 on Earth) t = time
In this case, we want to find the distance fallen in one second, so t = 1 second. Plugging in these values into the equation, we get:
d = (1/2) * 9.8 * (1)^2 d = 4.9 meters
Therefore, when the ball is dropped from a height of ten meters, it will fall a distance of approximately 4.9 meters in one second.