To find the maximum height reached by the stone, we need to use the equations of motion. Given that the stone is thrown vertically upward with an initial velocity of 4.9 m/s, we can use the following equation:
v² = u² + 2as
where: v = final velocity (which is 0 m/s at the maximum height, as the stone momentarily stops before falling down) u = initial velocity (4.9 m/s upward) a = acceleration (which is the acceleration due to gravity, approximately -9.8 m/s² in the opposite direction of motion) s = displacement (maximum height reached)
Plugging in the values, we have:
0² = (4.9)² + 2(-9.8)s
Simplifying the equation:
0 = 24.01 - 19.6s
Rearranging the equation to solve for s:
19.6s = 24.01
s = 24.01 / 19.6
s ≈ 1.225 meters
Therefore, the maximum height reached by the stone is approximately 1.225 meters.