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To solve this problem, we can use the kinematic equation:

v = u + at

where: v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given information: Initial velocity (u) = -5 m/s (negative because the car is going backwards) Final velocity (v) = 10 m/s Time (t) = 10 seconds

Using the given information, we can rewrite the equation as:

10 m/s = -5 m/s + a(10 s)

To find the acceleration (a), we need to isolate it on one side of the equation. Let's simplify the equation:

10 m/s + 5 m/s = a(10 s) 15 m/s = 10a

Divide both sides by 10 to solve for the acceleration:

15 m/s / 10 s = 10a / 10 s 1.5 m/s² = a

Therefore, the acceleration of the car is 1.5 m/s².

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