Question

A stone is thrown vertically upwards with a speed of 5 meters per second. How high does the stone rise before returning back to the earth given acceleration due to the earth's attraction acceleration is equal to 9.8m?

Answer 1

To determine the maximum height reached by the stone when thrown vertically upwards, we can use the following kinematic equation:

v² = u² + 2as

where: v = final velocity (which is 0 m/s at the maximum height) u = initial velocity (5 m/s upwards) a = acceleration (acceleration due to gravity, -9.8 m/s²) s = displacement (unknown, the height we want to find)

Rearranging the equation, we get:

s = (v² - u²) / (2a)

Plugging in the values:

s = (0² - 5²) / (2 * -9.8) s = (-25) / (-19.6) s ≈ 1.275 meters

Therefore, the stone rises to a height of approximately 1.275 meters before returning back to the Earth.