Certainly! Radioactive decay involves the transformation of an unstable parent isotope into a more stable daughter isotope. In some cases, the daughter isotope can have a higher binding energy per nucleon than the parent, indicating greater stability. Here are a few examples:
Uranium-238 (parent) decays into Thorium-234 (daughter): Uranium-238, with a binding energy per nucleon of approximately 7.6 MeV, undergoes alpha decay, producing Thorium-234. Thorium-234 has a slightly higher binding energy per nucleon of around 7.6-7.7 MeV.
Polonium-210 (parent) decays into Lead-206 (daughter): Polonium-210, with a binding energy per nucleon of approximately 7.5 MeV, undergoes alpha decay to become Lead-206. Lead-206 has a higher binding energy per nucleon of around 7.6-7.7 MeV.
Radon-222 (parent) decays into Polonium-218 (daughter): Radon-222, with a binding energy per nucleon of around 7.5 MeV, undergoes alpha decay to form Polonium-218. Polonium-218 has a slightly higher binding energy per nucleon of approximately 7.6 MeV.
In these examples, although the difference in binding energy per nucleon between the parent and daughter isotopes is relatively small, the daughter isotopes are considered more stable due to the rearrangement of nucleons resulting from the decay process.
It's important to note that the binding energy per nucleon can vary slightly depending on the specific isotopes and their nuclear configurations. The values provided here are approximate and meant to illustrate the general concept of radioactive decay where the daughter isotope can have a higher binding energy per nucleon than the parent.