+11 votes
in Physics by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+3 votes
by

To calculate the distance traveled by a car when it accelerates from rest to a speed of 45 km/hr in 6 seconds, we need to find the average speed during that time period and then multiply it by the time.

First, let's convert the speeds to meters per second (m/s) for consistent units:

Initial speed (rest): 0 km/hr = 0 m/s Final speed: 45 km/hr = (45 * 1000) m/3600 s ≈ 12.5 m/s

Now we can calculate the average speed:

Average speed = (Initial speed + Final speed) / 2 = (0 m/s + 12.5 m/s) / 2 = 6.25 m/s

The time taken is given as 6 seconds.

Using the formula: Distance = Average speed * Time

Distance = 6.25 m/s * 6 s = 37.5 meters

Therefore, the distance traveled by the car during the acceleration phase is approximately 37.5 meters.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...