The distance covered by a freely falling body in two seconds can be determined using the equations of motion for constant acceleration. In the case of free fall near the surface of the Earth, assuming negligible air resistance, the acceleration due to gravity is approximately 9.8 m/s².
The equation to calculate the distance covered (d) by a freely falling body in time (t) with initial velocity (u) of zero and constant acceleration (a) is:
d = 0.5 * a * t^2
Plugging in the values:
a = 9.8 m/s² t = 2 s
d = 0.5 * 9.8 m/s² * (2 s)^2 d = 0.5 * 9.8 m/s² * 4 s^2 d = 19.6 m
Therefore, a freely falling body near the surface of the Earth would cover a distance of approximately 19.6 meters in two seconds.