Question

A 0.23 kg stone is thrown 17 m and reaches the ground at a speed of 13 m/s. If there had been no air resistance, how quickly would the stone have landed?

Answer 1

To determine the time it would take for the stone to land if there were no air resistance, we can use the kinematic equation for vertical motion:

$v_f^2=v_i^2+2a\cdot d$

Where: $v_f$ is the final velocity (which is 0 m/s when the stone lands), $v_i$ is the initial velocity (which is unknown), $a$ is the acceleration due to gravity (-9.8 m/s²), $d$ is the vertical distance traveled (17 m).

Rearranging the equation, we have:

$v_i^2=v_f^2-2a\cdot d$

Substituting the known values:

vi2=02−2⋅(−9.8 m/s2)⋅17 mv_i^2 = 0^2 - 2 cdot (-9.8 , ext{m/s}^2) cdot 17 , ext{m}vi2​=02−2⋅<span class="msp