To determine the initial horizontal and vertical velocities of a projectile, we can use the given information about the bullet's launch speed and launch angle.
Given: Initial launch speed (v₀): 120 m/s Launch angle (θ): 55 degrees
We can break down the initial velocity (v₀) into its horizontal (v₀x) and vertical (v₀y) components using trigonometry.
Horizontal velocity (v₀x): v₀x = v₀ * cos(θ)
Vertical velocity (v₀y): v₀y = v₀ * sin(θ)
Let's calculate the values:
v₀x = 120 m/s * cos(55 degrees) ≈ 64.54 m/s (rounded to two decimal places) v₀y = 120 m/s * sin(55 degrees) ≈ 98.22 m/s (rounded to two decimal places)
Therefore, the initial horizontal velocity (v₀x) is approximately 64.54 m/s, and the initial vertical velocity (v₀y) is approximately 98.22 m/s.