When an object is dropped from a height of 100m from the surface of the Earth, we can use the equations of motion to determine the distance traveled by the object after a given time. Assuming there is no air resistance, we can use the equation:
s = ut + (1/2)at^2
where: s is the distance traveled u is the initial velocity (0 m/s because it is dropped) t is the time (3 seconds) a is the acceleration due to gravity (-9.8 m/s^2, assuming downward direction)
Plugging in the values:
s = 0(3) + (1/2)(-9.8)(3)^2 s = 0 + (1/2)(-9.8)(9) s = 0 + (-4.9)(9) s = -44.1 meters
The negative sign indicates that the object has fallen downward. Therefore, after 3 seconds, the object will have traveled a distance of 44.1 meters downward from its starting point, which means it will be at a height of 100m - 44.1m = 55.9 meters above the surface of the Earth.