To find the distance traveled by the car during the 10 seconds, we can use the equation:
Distance=Average Velocity×Time ext{Distance} = ext{Average Velocity} imes ext{Time}Distance=Average Velocity×Time
In this case, since the car is accelerating, we need to calculate the average velocity over the given time interval.
Average Velocity can be calculated as:
Average Velocity=Initial Velocity+Final Velocity2 ext{Average Velocity} = frac{ ext{Initial Velocity} + ext{Final Velocity}}{2}Average Velocity=2Initial Velocity+Final Velocity
Given: Initial Velocity (v1v_1v1) = 20 m/s Final Velocity (v2v_2v2) = 40 m/s Time (ttt) = 10 seconds
Calculating the Average Velocity: Average Velocity=20 m/s+40 m/s2=30 m/s ext{Average Velocity} = frac{20 , ext{m/s} + 40 , ext{m/s}}{2} = 30 , ext{m/s}Average Velocity=220m/s+40m/s=30m/s
Now, we can find the distance traveled: Distance=Average Velocity×Time=30 m/s×10 s=300 meters ext{Distance} = ext{Average Velocity} imes ext{Time} = 30 , ext{m/s} imes 10 , ext{s} = 300 , ext{meters}Distance=Average Velocity×Time=30m/s×10s=300meters
Therefore, the car travels a distance of 300 meters during the 10 seconds.