In a Young's double-slit experiment, the interference pattern arises from the superposition of waves from two coherent sources. The intensity at any point on the screen depends on the amplitudes of the waves from the two slits and their phase relationship.
The ratio of intensities between the bright fringes (maxima) and dark fringes (minima) in the interference pattern is given by the square of the ratio of the amplitudes. If the ratio of intensity of the maxima and minima is infinite, it implies that the intensity at the bright fringes is infinitely greater than the intensity at the dark fringes.
Mathematically, if we denote the amplitudes of the waves from the two sources as A₁ and A₂, respectively, the ratio of intensities is given by:
(Intensity at maxima) / (Intensity at minima) = (A₁² + A₂²) / (A₁²)
Since the ratio of intensity at maxima and minima is infinite, it means that (A₁² + A₂²) is infinitely greater than A₁². Therefore, we can conclude that the amplitude of the wave from the second source (A₂) must dominate over the amplitude of the wave from the first source (A₁) in this scenario.
To determine the exact values of the amplitudes A₁ and A₂, more information or specific constraints would be required.