According to the principles of special relativity, when two observers are in relative motion, time dilation occurs, meaning that their clocks will measure time differently. In the scenario you described, where twins A and B depart from triplet X in opposite directions at the same speed and reach equidistant space stations C and D, time dilation will indeed occur.
From the perspective of triplet X, both twins A and B are in motion relative to X. Therefore, according to special relativity, time dilation will affect both twins A and B equally, and their clocks will appear to run slower relative to the clock in X.
However, from the perspective of twin A, twin B is in motion and moving away. According to special relativity, time dilation occurs due to relative motion. Therefore, from twin A's perspective, twin B's clock will appear to run slower compared to their own clock.
Similarly, from the perspective of twin B, twin A is in motion and moving away. Again, due to relative motion, time dilation will occur. Thus, from twin B's perspective, twin A's clock will appear to run slower compared to their own clock.
It's important to note that time dilation is a relative effect, and each observer will observe the other's clock as running slower than their own. This phenomenon is known as the twin paradox, where twins who experience different accelerations and changes in direction during their journey will eventually reunite with one twin having aged less than the other.
In summary, according to special relativity, each twin will observe the other's clock running slower due to time dilation resulting from their relative motion.