+26 votes
in Science of Everyday Life by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+1 vote
by

To find the n-factor (also known as the oxidation state or oxidation number) of a complex compound, you generally follow these steps:

  1. Identify the elements present in the compound: Determine the elements and their respective symbols in the complex compound.

  2. Determine the known oxidation states: Look for any elements in the compound that have a known or commonly observed oxidation state. This information can be obtained from periodic tables or general knowledge about oxidation states.

  3. Assign oxidation states to other elements: Once you have identified the known oxidation states, assign oxidation states to the remaining elements based on the known rules and guidelines for assigning oxidation states. Some common rules include:

    • The sum of oxidation states in a neutral compound is zero.
    • The sum of oxidation states in a polyatomic ion is equal to the charge of the ion.
    • In general, hydrogen is assigned an oxidation state of +1 and oxygen is assigned an oxidation state of -2. However, there may be exceptions depending on the compound.
  4. Calculate the n-factor: The n-factor is the change in oxidation state of an element during a chemical reaction. To calculate the n-factor for a compound, you subtract the initial oxidation state from the final oxidation state for the element that changes its oxidation state.

For example, let's consider the compound KMnO4:

  • The oxidation state of potassium (K) is +1 (commonly observed for alkali metals).
  • The oxidation state of oxygen (O) is -2 (commonly observed for oxygen in most compounds).
  • Since the compound is neutral, the sum of the oxidation states must be zero.
  • Let's assume the oxidation state of manganese (Mn) is x.
  • Applying the rules, we have: (+1) + x + 4(-2) = 0
  • Solving the equation, we find x = +7 for manganese.

In this case, the n-factor of KMnO4 is +6, as manganese changes from an oxidation state of +7 (in KMnO4) to +1 (in Mn2+ in a reduction reaction).

It's important to note that determining oxidation states can sometimes be more complex for certain compounds or coordination complexes. In such cases, you may need to consider the coordination geometry and ligand effects, as well as any charge on the complex.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...