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In the relation a = 2v, where 'a' represents acceleration and 'v' represents velocity, we can determine the velocity as a function of time by integrating the acceleration with respect to time.

Let's assume that at t = 0, the velocity is v0. Then, integrating the given relation with respect to time, we have:

∫ a dt = ∫ 2v dt

Integrating both sides gives:

∫ a dt = ∫ 2v dt at = 2∫ v dt

Integrating the right side with respect to 't' gives:

at = 2 ∫ v dt at = 2vt + C

Here, 'C' represents the constant of integration, which arises due to the indefinite integration.

Now, solving for velocity 'v,' we get:

at = 2vt + C 2vt = at - C v = (at - C) / (2t)

The expression for velocity 'v' as a function of time 't' in the given relation a = 2v is:

v = (at - C) / (2t)

Please note that without specific initial conditions or information about the constant 'C,' it is not possible to determine the exact velocity as a function of time in this case.

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