To find the acceleration of the object, we can use the kinematic equation:
v2=u2+2asv^2 = u^2 + 2asv2=u2+2as
where: vvv = final velocity = 125 m/s uuu = initial velocity = 0 m/s (starting from rest) sss = displacement = 625 m aaa = acceleration (what we need to find)
Since the object starts from rest (u=0u = 0u=0), we can simplify the equation to:
v2=2asv^2 = 2asv2=2as
Now, we can plug in the given values and solve for acceleration (aaa):
1252=2×a×625125^2 = 2 imes a imes 6251252=2×a×625
15625=1250a15625 = 1250a15625=1250a
Now, isolate aaa by dividing both sides of the equation by 1250:
a=156251250=12.5 m/s2a = frac{15625}{1250} = 12.5 , ext{m/s}^2a=125015625=12.5m/s2
So, the acceleration