To find the distance traveled by a body with an initial velocity, constant acceleration, and a given time, we can use the following equation:
s = ut + (1/2)at^2
Where: s = distance traveled u = initial velocity a = acceleration t = time
Given: u = 20 m/s (initial velocity) a = 5 m/s^2 (acceleration) t = 15 s (time)
Plugging in the values, we have:
s = (20 * 15) + (1/2) * 5 * (15)^2 s = 300 + 1/2 * 5 * 225 s = 300 + 1/2 * 1125 s = 300 + 562.5 s = 862.5 meters
Therefore, the distance traveled by the body in 15 seconds is 862.5 meters.