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If a vehicle is moving with a velocity of 20 m/s and it comes to a stop after 4 seconds, we can assume that the vehicle undergoes constant deceleration (negative acceleration) until it reaches a velocity of 0 m/s.

To find the final velocity, we can use the formula for uniformly accelerated motion:

vf=vi+atv_f = v_i + at

where:

  • vfv_f is the final velocity,
  • viv_i is the initial velocity,
  • aa is the acceleration, and
  • tt is the time.

In this case, the initial velocity (viv_i) is 20 m/s, the final velocity (vfv_f) is 0 m/s, and the time (tt) is 4 seconds.

Since the vehicle is decelerating, the acceleration (aa) will be negative. We'll denote it as −a-a.

Plugging the given values into the formula, we have:

0=20+(−a)⋅40 = 20 + (-a) cdot 4

Simplifying the equation:

0=20−4a0 = 20 - 4a

N

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