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To calculate the final speed of the car at the end of 4.0 seconds, you can use the following kinematic equation:

v=u+atv = u + at

Where:

  • vv is the final velocity (the speed we want to find).
  • uu is the initial velocity (which is 0 m/s for a car starting from rest).
  • aa is the acceleration of the car (given as 8.0 m/s28.0 , ext{m/s}^2).
  • tt is the time it takes to reach the final velocity (given as 4.0 s4.0 , ext{s}).

Substitute the given values into the equation and solve for vv:

v=0 m/s+(8.0 m/s2)×4.0 sv = 0 , ext{m/s} + (8.0 , ext{m/s}^2) imes 4.0 , ext{s}

v=0 m/s+32.0 m/sv = 0 , ext{m/s} + 32.0 , ext{m/s}

v=32.0 m/sv = 32.0 , ext{m/s}

The final speed of the car at the end of 4.0 seconds is 32.0 m/s32.0 , ext{m/s} or 32.0 meters per second32.0 , ext{meters per second}.

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