To calculate the final speed of the car at the end of 4.0 seconds, you can use the following kinematic equation:
v=u+atv = u + atv=u+at
Where:
- vvv is the final velocity (the speed we want to find).
- uuu is the initial velocity (which is 0 m/s for a car starting from rest).
- aaa is the acceleration of the car (given as 8.0 m/s28.0 , ext{m/s}^28.0m/s2).
- ttt is the time it takes to reach the final velocity (given as 4.0 s4.0 , ext{s}4.0s).
Substitute the given values into the equation and solve for vvv:
v=0 m/s+(8.0 m/s2)×4.0 sv = 0 , ext{m/s} + (8.0 , ext{m/s}^2) imes 4.0 , ext{s} v=0m/s+(8.0m/s2)×4.0s
v=0 m/s+32.0 m/sv = 0 , ext{m/s} + 32.0 , ext{m/s} v=0m/s+32.0m/s
v=32.0 m/sv = 32.0 , ext{m/s}v=32.0m/s
The final speed of the car at the end of 4.0 seconds is 32.0 m/s32.0 , ext{m/s}32.0m/s or 32.0 meters per second32.0 , ext{meters per second}32.0meters per second.