To find the acceleration and distance traveled by the car, we can use the kinematic equations of motion.
Given: Initial velocity, u = 0 (car starts from rest) Final velocity, v = 15 kph Time, t = 2 seconds
First, let's convert the final velocity from kph to m/s:
15 kph = (15 * 1000) / 3600 m/s ≈ 4.17 m/s
Using the equation:
v = u + at
where: v = final velocity u = initial velocity a = acceleration t = time
We can rearrange the equation to solve for acceleration:
a = (v - u) / t
Substituting the values:
a = (4.17 m/s - 0 m/s) / 2 s a = 2.085 m/s^2
The acceleration of the car is approximately 2.085 m/s^2.
To find the distance traveled by the car, we can use the equation:
s = ut + (1/2)at^2
where: s = distance u = initial velocity t = time a = acceleration
Substituting the values:
s = 0 m/s * 2 s + (1/2) * 2.085 m/s^2 * (2 s)^2 s = 0 m + (1/2) * 2.085 m/s^2 * 4 s^2 s = 0 m + 4.17 m s = 4.17 m
The car travels a distance of approximately 4.17 meters.