Question

A car traveling at 10 m/s increases its speed with a uniform rate of 3m/s2 for 10 seconds. How far has the car travelled after 10 seconds?

Answer 1

To determine the distance traveled by the car after 10 seconds, we can use the equation:

$d=v_{i}t+\frac{1}{2}a{t}^2$

where:

• $d$ represents the distance traveled
• $v_i$ is the initial velocity
• $a$ is the uniform acceleration
• $t$ is the time

Given:

• Initial velocity, $v_i=10\text{m/s}$
• Uniform acceleration, $a=3{\text{m/s}}^2$
• Time, $t=10\text{s}$

Plugging these values into the equation, we get:

d=(10 m/s)×(10 s)+12(3 m/s2)×(10 s)2d = (10 , ext{m/s}) imes (10 , ext{s}) + frac{1}{2} (3 , ext{m/s}^2) imes (10 , ext{s})^2d=(10m/s)×(10s)+2</spa