Question

A car traveling along the x-axis from rest at x= 50 m and accelerates at a constant rate of 8.0 m/s^2. how fast is it goes after 10s? How far has it gone after 10s?

Answer 1

To determine the speed of the car after 10 seconds and the distance it has traveled, we can use the equations of motion.

1. Speed (velocity) of the car after 10 seconds:

The initial velocity (u) is 0 m/s (starting from rest), the time (t) is 10 seconds, and the acceleration (a) is 8.0 m/s².

We can use the equation:

v = u + at

Substituting the values:

v = 0 + (8.0 m/s²)(10 s) v = 80 m/s

Therefore, the speed of the car after 10 seconds is 80 m/s.

2. Distance traveled by the car after 10 seconds:

To find the distance traveled, we can use the equation:

s = ut + (1/2)at²

Substituting the values:

s = (0 m/s)(10 s) + (1/2)(8.0 m/s²)(10 s)² s = 0 + (1/2)(8.0 m/s²)(100 s²) s = 400 m

Therefore, the car has traveled a distance of 400 meters after 10 seconds.