Question

A bus traveling 50 m/s is increasing its speed at the rate of 4m/s². What is the distance covered in 6 seconds?

Answer 1

To find the distance covered by the bus in 6 seconds, we can use the equation of motion:

$s=ut+\frac{1}{2}a{t}^2$

Where:

• $s$ is the distance covered
• $u$ is the initial velocity
• $t$ is the time
• $a$ is the acceleration

Given: Initial velocity, $u=50\text{m/s}$ Acceleration, $a=4{\text{m/s}}^2$ Time, $t=6\text{s}$

Substituting the values into the equation, we get:

$s=(50\text{m/s})(6\text{s})+\frac{1}{2}(4{\text{m/s}}^2)(6\text{s}{)}^2$

Simplifying the equation, we have:

s=300 m+12(4 m/s2)<mo s