+9 votes
in Speed by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+6 votes
by

Let's assume the car's first speed (constant speed) is "x" km/h.

During the first 2 hours, the car covers a distance of 2 * x = 2x km.

In the next 3 hours, the car's speed is 4 km/h faster than the initial speed "x," so the speed is (x + 4) km/h. The distance covered during these 3 hours is 3 * (x + 4) = 3x + 12 km.

In the final 4 hours, the car's speed is 10 km/h slower than the initial speed "x," so the speed is (x - 10) km/h. The distance covered during these 4 hours is 4 * (x - 10) = 4x - 40 km.

The total distance covered by the car is 602 km. So, we can set up the equation:

Distance in first 2 hours + Distance in next 3 hours + Distance in final 4 hours = Total distance 2x + 3x + 12 + 4x - 40 = 602

Combine the "x" terms and constants:

9x - 28 = 602

Now, isolate "x" by moving the constant to the other side:

9x = 602 + 28 9x = 630

Finally, solve for "x" by dividing both sides by 9:

x = 630 / 9 x = 70

The first speed (constant speed) of the car is 70 km/h.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...