Question

A car is travelling at 20 m/s. It accelerates uniformly at 3 m/S2 for 5 s. What is the distance the car travels while it is accelerating?

Answer 1

To find the distance the car travels while it is accelerating uniformly, you can use the following kinematic equation:

$\text{Distance}=\text{Initial Velocity}\times \text{Time}+\frac{1}{2}\times \text{Acceleration}\times {\text{Time}}^2$

Given: Initial Velocity ($u$) = 20 m/s Acceleration ($a$) = 3 m/s² Time ($t$) = 5 s

Now, plug these values into the equation:

$\text{Distance}=20\text{m/s}\times 5\text{s}+\frac{1}{2}\times 3{\text{m/s}}^2\times (5\text{s}{)}^2$

Distance=100 m+12×3 m/s2×25 s2 ext{Distance} = 100 , ext{m} + frac{1}{2} imes 3 , ext{m/s}^2 imes 25 , ext{s}^2Distance=100m+21​<span class="ms